SOLUTION: Given: P1 (2,-3) & P2 (3,2), Construct the slope-intercept of the line.

Algebra ->  Coordinate Systems and Linear Equations  -> Lessons -> SOLUTION: Given: P1 (2,-3) & P2 (3,2), Construct the slope-intercept of the line.      Log On


   

Question 206275: Given: P1 (2,-3) & P2 (3,2), Construct the slope-intercept of the line.
Answer by Targetweek(62) About Me  (Show Source):
You can put this solution on YOUR website!
Slope Intercept form is y+=+mx+%2B+b
Well first of all slope equals rise over run or...
m+=+%28y2-y1%29%2F%28x2-x1%29 or m+=+%28DELTA%2Ay%29%2F%28DELTA%2Ax%29 (DELTA is jsut a fancy way of saying change in or final minus initial)
And your two points are (2,-3) and (3,2)
which means that...
x1 = 2
x2 = 3
y1 = -3
y2 = 2
So just plug those values in and solve for m
- m+=+%282-%28-3%29%29%2F%283-2%29
- m+=+5%2F1
= m+=+5
So your slope is a positive 5
Now that we have m, plug in m and one of your points into y = mx + b and solve for b
- y+=+mx+%2B+b
- 2+=+%285%29%283%29+%2B+b
- 2+=+15+%2B+b
- 2-15+=+15-15%2Bb
- -13+=+b
So your equation in slope intercept form is y+=+5x+-+13