
Multiply row 1 thru by -2 and add to row 2
Multiply row 1 by -1 and add to row 3
Multiply row 2 by -1 and add to row 3
Now we write the system of equations that this
matrix represents:
The bottom equation is all 0's so any values of
x, y, and z would be solutions to it, so we eliminate
it
Choose an arbitrary value for z, we will use
Or, after erasing the 0s and 1 coefficients:
Substitute
for
in the 2nd equation:
Solve for y
Substitute
for
and
for
in the first equation:
Clear of fractions:
So the solution is:
(x, y, z) = (
,
,
)
Edwin