SOLUTION: Solve 9/10 (7+2x)+2 ≥ 14 ----------- -------- 63/10 +9/5 x+2 ≥ 14 9/5x+83/10 ≥ 14 subtract 83/10 9/5x + 83/10-83/10 ≥ 14-83/10 9/5x ≥ ?/10 ( I'

Algebra ->  Coordinate Systems and Linear Equations  -> Lessons -> SOLUTION: Solve 9/10 (7+2x)+2 ≥ 14 ----------- -------- 63/10 +9/5 x+2 ≥ 14 9/5x+83/10 ≥ 14 subtract 83/10 9/5x + 83/10-83/10 ≥ 14-83/10 9/5x ≥ ?/10 ( I'      Log On


   

Question 202745: Solve
9/10 (7+2x)+2 ≥ 14
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63/10 +9/5 x+2 ≥ 14
9/5x+83/10 ≥ 14
subtract 83/10
9/5x + 83/10-83/10 ≥ 14-83/10
9/5x ≥ ?/10 ( I'm a little confuse and could you help me out here please?)
Then multiply 5/9
9/5x * 5/9 ≥ ?/10*5/9 (And here?)
x ≥ ?
Thank you!

Found 2 solutions by jim_thompson5910, rfer:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
%289%2F10%29%287%2B2x%29%2B2%3E=14 Start with the given inequality.


63%2F10%2B%289%2F5%29x%2B2%3E=14 Distribute.


Multiply EVERY term by the LCD 10 to clear any fractions.


Note: clearing out the fractions is not necessary, but it helps simplify things.


63%2B18x%2B20%3E=140 Multiply and simplify.


18x%2B83%3E=140 Combine like terms on the left side.


18x%3E=140-83 Subtract 83 from both sides.


18x%3E=57 Combine like terms on the right side.


x%3E=%2857%29%2F%2818%29 Divide both sides by 18 to isolate x.


x%3E=19%2F6 Reduce.


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Answer:

So the solution is x%3E=19%2F6

Answer by rfer(16322) About Me  (Show Source):
You can put this solution on YOUR website!
I like to use decimals when ever I can because it is easier.
9/10(7+2x)+2equal to or greater than 14
I will use = sign for ease of operation
9/10*7/10+2x/10+20/10=140/10
63/10+18x/10+20/10=140/10
18x/10=140/10-83/10
18/10(x)=57/10 remember, to divide, invert and multiply
x is equal to or greater than(57/10)(10/18)= 570/180=19/6=3.16
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.9(7+2x)+2=14
6.3+1.8x+2=14
1.8x=14-8.3
1.8x=5.7
x= is equal to or greater than 3.16