SOLUTION: Please help me solve:
Soybean meal is 14% protein; cornmeal is 7% protein. How many pounds of each should be mixed together in order to get 280lbs mixture that is 12% protein?
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Soybean meal is 14% protein; cornmeal is 7% protein. How many pounds of each should be mixed together in order to get 280lbs mixture that is 12% protein?
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Question 198842: Please help me solve:
Soybean meal is 14% protein; cornmeal is 7% protein. How many pounds of each should be mixed together in order to get 280lbs mixture that is 12% protein?
How many pounds of the cornmeal should be in the misture?
How many pounds of the soybean should be in the mixture?
Thank you. Answer by jim_thompson5910(35256) (Show Source):
Since we want a 280 lbs mixture, this means that we have the first equation:
Also, because we want a "280-lb mixture that is 12% protein" from the mixture of
soybean meal that is 14% protein and cornmeal that is 7% protein, we have the second equation:
Start with the second equation.
Multiply
Multiply both sides by 100 to remove the decimals
Distribute
So we have the new system of equations:
Let's solve the system by use of substitution
Now in order to solve this system by using substitution, we need to solve (or isolate) one variable. I'm going to solve for y.
So let's isolate y in the first equation
Start with the first equation
Subtract from both sides
Rearrange the equation
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Since , we can now replace each in the second equation with to solve for
Plug in into the second equation. In other words, replace each with . Notice we've eliminated the variables. So we now have a simple equation with one unknown.