Question 198244This question is from textbook
: Joe has a collection of nickels and dimes that is worth $5.65. If the number of dimes were doubled and the number of nickels were increased by 8, the value of the coins would be $10.45. How many dimes does he have?
This question is from textbook
Answer by RAY100(1637)   (Show Source):
You can put this solution on YOUR website! Let D = no of Dimes, and N = no of Nickels
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1) .1 D + .05 N = 5.65
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2) .1(2D) +.05( N+8) = 10.45
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or .2D +.05N +.40 =10.45
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or .2D +.05N = 10.05
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substract 2) - 1)
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.1D = 4.40
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D = 44
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Subst in 1) .1(44) + .05 N = 5.65
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4.4 + .05 N = 5.65
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.05 N = 1.25
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N = 25
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check,,1) .1(44) + .05(25) = 5.65,,,,ok
2) .1(88) + .05(33) = 10.45,,, ok
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