SOLUTION: Ok, I am lost.I now have parallel to the lines. I need to find an equation of the line that is parallel to the line y=7x-3 and passes thru the point (8,7). I thought the answer wa

Algebra ->  Coordinate Systems and Linear Equations  -> Lessons -> SOLUTION: Ok, I am lost.I now have parallel to the lines. I need to find an equation of the line that is parallel to the line y=7x-3 and passes thru the point (8,7). I thought the answer wa      Log On


   



Question 173853: Ok, I am lost.I now have parallel to the lines. I need to find an equation of the line that is parallel to the line y=7x-3 and passes thru the point (8,7). I thought the answer was v-7 h-3 but am not positive.? Ty in advance. Judy
Found 5 solutions by solver91311, jojo14344, stanbon, monika_p, Fombitz:
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!
Rule 1: Parallel lines have equal slopes.

Your given equation is in slope-intercept form y=mx%2Bb, so you can tell by inspection that the slope of the given line is 7.

Next you need to use the point-slope form of the line to find the desired equation. The equation of a line with slope m passing through point (x%5B1%5D,y%5B1%5D) is y-y%5B1%5D=m%28x-x%5B1%5D%29, so just substitute the values you know, namely the slope, m=+blue%287%29 and the coordinates of the given point: (green%28x%5B1%5D%29,red%28y%5B1%5D%29) = (green%288%29,red%287%29).




You should rearrange y-7=7%28x-8%29 by solving for y to put your equation for the desired line into slope-intercept form to match the given equation. I'll leave that as an exercise for the student.

Answer by jojo14344(1513) About Me  (Show Source):
You can put this solution on YOUR website!
I need to find an equation of the line that is parallel to the line y=7x-3 and passes thru the point (8,7).
.

okay, slope=m of line y=7x-3 is m%5B1%5D=7. Since the line are parallel, m%5B1%5D=m%5B2%5D=7.
Therefore, thru point (8,7), we can get the y-intercept via Slope-intercept Form: y=mx%2Bb
7=7%2A8%2Bb
7=56%2Bb ----->b=7-56=-49, y-intercept.
Then, line eqn is----->highlight%28y=7x-49%29, or highlight%28-7x%2By%2B49=0%29 Standard Form
We see the graph:
-------> RED, Line y=7x-3; GREEN, Line y=7x-49
Thank you,
Jojo


Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
find an equation of the line that is parallel to the line y=7x-3 and passes thru the point (8,7).
------------------
If parallel to y = 7x-3, the slope is 7
---------------------
Form: y = mx + b
7 = 7*8 + b
7 = 56 + b
b = -49
---------
Equation:
y = 7x - 49
=============
Cheers,
Stan H.

Answer by monika_p(71) About Me  (Show Source):
You can put this solution on YOUR website!
If the lines are parallel it means that they have same slope.
The basic form of line y=mx+b m is a slope, then y=7x-3 slope m =7
Using "point-slope" form of the line y-y1=m(x-x1) you can find equation of the line passing through the point (x1,y1)----(8,7)
y-7=7(x-8)
y=7x-49-----answer

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Parallel lines have identical slopes.
The slope of your new line is identical to the old line,
m=7
Use the point-slope form of the line,
y-y%5Bp%5D=m%28x-x%5Bp%5D%29
where x%5Bp%5D=8 and y%5Bp%5D=7,
y-7=7%28x-8%29
y-7=7x-56
highlight%28y=7x-49%29
.
.
.
Here are both lines graphed, along with point (8,7), as visual proof of the solution.