SOLUTION: if a company plans to lay off 10% of its employees in its aerospace division and 15% of its employees in its agricultural divsion. If altogether 12% of the 3000 employees in these
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Question 162853: if a company plans to lay off 10% of its employees in its aerospace division and 15% of its employees in its agricultural divsion. If altogether 12% of the 3000 employees in these two division will be laid off, then how many employees are in each divsion.
Heres what I've tried: .10 (x) + .15(x) +.12 = 3000
300 450
.12x = 3000
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.12 .12 Answer by jim_thompson5910(35256) (Show Source):
From the problem, we know that there are a total of 3,000 employees from both divisions. So this means that the sum of the two groups will be 3,000. This means that
Also, since 12% of the total workers will be laid off, this means that 0.12(3000)=360 employees will be laid of in total in these two divisions. So the sum of the layoffs in the aerospace division (which is 10% of "x" and is represented by 0.10x) and the layoffs in the aerospace division (which is 15% of "y" and is represented by 0.15y) will equal 360. This translates to: )
Start with the second equation
Multiply EVERY term by 100 to make every number a whole number. Note: this will move the decimal point two spots to the right.
So we have the system of equations:
Multiply the both sides of the first equation by -10.
Distribute and multiply.
So we have the new system of equations:
Now add the equations together. You can do this by simply adding the two left sides and the two right sides separately like this:
Group like terms.
Combine like terms. Notice how the x terms cancel out.
(