SOLUTION: the perimeter of a rectangle is 60 inches and the length is 4 inches longer than the width. Find the dimensions of the triangle.

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Question 156649: the perimeter of a rectangle is 60 inches and the length is 4 inches longer than the width. Find the dimensions of the triangle.
Found 2 solutions by mizjoice, Electrified_Levi:
Answer by mizjoice(22) About Me  (Show Source):
You can put this solution on YOUR website!
Once you know the rules you can break them! In algebra, start with the formula. the formula for a perimeter is P=2(w + l). I don't have a conventional way of solving for the perimeter but this does work. The perimeter of the rectangle is 60 inches. The first thing is do is divide by four.60/4=15. now, if this perimeter is 15 on all sides, that's not a rectangle, thats a square! But remember, the length is 4 inches longer than the width. Add 2 inches to two sides 15 + 2 =17. Now take two from the other side15-2=13. Check your answer 17-4=13. And double check by substituting values: P = 2(17+13) P=34+26 P=60

Answer by Electrified_Levi(103) About Me  (Show Source):
You can put this solution on YOUR website!
Hi, Hope I can help,
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the perimeter of a rectangle is 60 inches and the length is 4 inches longer than the width. Find the dimensions of the triangle.(I think you mean "Find the dimensions of the rectangle)
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The perimeter is all the sides added together, in this case there are 4 sides
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We need to assign variables to the length and width .
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the length is 4 inches longer than the width. ( we can say that the width is "x" ), if the length is 4 inches longer than the width, the length = "x+4"
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Length = "x+4"
Width = "x"
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Our Perimeter = 60, Perimeter of Rectangle = +2%28Length%29+%2B+2%28Width%29+ = +2%28L%29+%2B+2%28W%29+, we can replace "L" and "W" with the length and width variables
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(since we already have our perimeter, "60", we can say +2%28L%29+%2B+2%28W%29+=+60+ )
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Let's replace "L" with "x+4", "W" with "x",(since we already have our perimeter, "60", we can say +2%28L%29+%2B+2%28W%29+=+60+
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+2%28L%29+%2B+2%28W%29+=+60+ = +2%28x%2B4%29+%2B+2%28x%29+=+60+
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We will use distribution
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+2%28x%2B4%29+%2B+2%28x%29+=+60+ =
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+2x+%2B+8+%2B+2x+=+60+
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Now let us rearrange the numbers
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+2x+%2B+8+%2B+2x+=+60+ = +2x+%2B+2x+%2B+8+=+60+
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We will now add like terms +cartoon+%28+highlight%282x%29+%2B+highlight%282x%29+%2B+8+=+60%2C+4x+%2B+8+=+60%29+
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+4x+%2B+8+=+60+
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Now lets move the "8" to the right side
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+cartoon+%28+4x+%2B+8+=+60%2C+4x+%2B+8+-8+=+60+-8%2C+4x+=+60-8%2C+4x+=+52%29+
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+4x+=+52+
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Now lets divide each side by "4" to find "x"
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+x+=+13+
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Just replace "x" with 13 in our length and width variables
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Length = "x+4" = "13+4" = "17"
Width = "x" = "13"
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Length = "17"
Width = "13"
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We can check by replacing "L"(Length) with "17", "W"(Width) with "13" in our equation, or by replacing "x" with "13" in one of the other equations
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+2%28L%29+%2B+2%28W%29+=+60+ = +2%2817%29+%2B+2%2813%29+=+60+ = +34+%2B+26+=+60+ = +60+=+60+ (True)
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Or we can check this way, by replacing "x" with "13"
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+2%28x%2B4%29+%2B+2%28x%29+=+60+ = +2%2813%2B4%29+%2B+2%2813%29+=+60+ = +2%2817%29+%2B+2%2813%29+=+60+ = +2%2817%29+%2B+2%2813%29+=+60+ = +34+%2B+26+=+60+ = +60+=+60+
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the length(17) is 4 inches longer than the width(13) "True"
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Length = "17 inches"
Width = "13 inches"
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Hope I helped, Levi