SOLUTION: 11+g+4-9=30 11+4m=4m+8 6a=2(4-a) 20=-5/4a 2(h-3)=5+13 how to solve it?

Algebra ->  Coordinate Systems and Linear Equations  -> Lessons -> SOLUTION: 11+g+4-9=30 11+4m=4m+8 6a=2(4-a) 20=-5/4a 2(h-3)=5+13 how to solve it?      Log On


   

Question 156160: 11+g+4-9=30
11+4m=4m+8
6a=2(4-a)
20=-5/4a
2(h-3)=5+13
how to solve it?
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
I'll do the first three to get you started

# 1



11%2Bg%2B4-9=30 Start with the given equation.


g%2B6=30 Combine like terms on the left side.


g=30-6 Subtract 6 from both sides.


g=24 Combine like terms on the right side.


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Answer:

So the answer is g=24





# 2



11%2B4m=4m%2B8 Start with the given equation.


4m=4m%2B8-11 Subtract 11 from both sides.


4m-4m=8-11 Subtract 4m from both sides.


0m=8-11 Combine like terms on the left side.


0m=-3 Combine like terms on the right side.


0=-3 Simplify.


Since this equation is never true for any m value, this means that there are no solutions. So the equation is inconsistent.





# 3



6a=2%284-a%29 Start with the given equation.


6a=8-2a Distribute.


6a%2B2a=8 Add 2a to both sides.


8a=8 Combine like terms on the left side.


a=%288%29%2F%288%29 Divide both sides by 8 to isolate a.


a=1 Reduce.


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Answer:

So the answer is a=1