Add equations 1 and 2. Let's call the result equation 4:
+
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Equation 4:
Multiply both sides of equation 1 by 2
Multiply. Let's call this equation 5
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Multiply both sides of equation 3 by 3
Multiply. Let's call this equation 6
Now add equations 5 and 6. Let's call the result equation 7:
+
-------------------
Equation 7:
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So we now have the two equations equation 4 and equation 7:
equation 4:
equation 7:
Start with the given system of equations:
Now in order to solve this system by using substitution, we need to solve (or isolate) one variable. I'm going to solve for z.
So let's isolate z in the first equation
Start with the first equation
Subtract from both sides
Rearrange the equation
Divide both sides by
Break up the fraction
Reduce
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Since , we can now replace each in the second equation with to solve for
Plug in into the first equation. In other words, replace each with . Notice we've eliminated the variables. So we now have a simple equation with one unknown.
Distribute to
Multiply
Multiply both sides by the LCM of 3. This will eliminate the fractions (note: if you need help with finding the LCM, check out this solver)
Distribute and multiply the LCM to each side
Combine like terms on the left side
Add 88 to both sides
Combine like terms on the right side
Divide both sides by 46 to isolate x
Divide
So the first part of our answer is:
Since we know that we can plug it into the equation (remember we previously solved for in the first equation).
Start with the equation where was previously isolated.
Plug in
Multiply
Combine like terms and reduce. (note: if you need help with fractions, check out this solver)