SOLUTION: Please help with this problem.
Z=sqrt((1000^2)+(1592^2))
It is my understanding that the square root of a "number" squared is the "number".
If this is true I would solve this as
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Z=sqrt((1000^2)+(1592^2))
It is my understanding that the square root of a "number" squared is the "number".
If this is true I would solve this as
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Question 150807: Please help with this problem.
Z=sqrt((1000^2)+(1592^2))
It is my understanding that the square root of a "number" squared is the "number".
If this is true I would solve this as: Z=1000+1592 so Z=2592, but Im not sure this is correct Found 4 solutions by jim_thompson5910, ankor@dixie-net.com, Earlsdon, Edwin McCravy:Answer by jim_thompson5910(35256) (Show Source):
You can put this solution on YOUR website! Z=sqrt((1000^2)+(1592^2))
No, if there were a * (multiply) between them it would be 1000*1592
but if there's a plus or a minus you have to do the math inside the radical
then find the square root of that
:
You can prove this to yourself with a calc: Enter = 1880...
You can put this solution on YOUR website! Evaluate:
While your statement - "...the square root of a 'number' squared is the 'number'." is true, your conclusion is faulty.
You can easily see this in the Pytagorean theorem: Taking the square root of both sides we get... and this is NOT the same as because the sum of the squares is not the same as the sum of the numbers, so... Square the numbers under the radical sign. Add the numbers under the radical sign. Now extract the square root. ...and this is an irrational number (a non-repeating, non-terminating decimal).
You can put this solution on YOUR website! Please help with this problem.
Z=sqrt((1000^2)+(1592^2))
It is my understanding that the square root of a "number" squared is the "number".
If this is true I would solve this as: Z=1000+1592 so Z=2592, but Im not sure this is correct
This is a very common error in mathematics.
Notice that when there is only MULTIPLICATION under the radical,
what you did would have been correct:
is TRUE because
However, when there is ADDITION or SUBTRACTION
under the radical, that does NOT WORK:
is FALSE because
So what you did won't work because of the PLUS SIGN
under the radical. If they had been MULTIPLIED under
the radical, then you could have.
If the problem had been this then the
answer would have been and then
However there was ADDITION under the radical, so you cannot
take individual square roots. All you can do is do whatever
you can under the radical FIRST.
That's the simplest radical form.
The approximate decimal value is
----------------------
Notice that
Howver,
Math rules that work when things are MULTIPLIED or
DIVIDED will NEVER work for things ADDED or
SUBTRACTED.
and likewise:
Math rules that work for things ADDED or SUBTRACTED
will NEVER work for things MULTIPLIED or DIVIDED.
Edwin
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