Question 141292This question is from textbook prentice hall algebra 1
: How do I solve using a system of two equations in two variables?
Four years ago, Katie was twice as old as Anne was then. In 6 years, Anne will be the same age as Katie is now. How old is each now?
This question is from textbook prentice hall algebra 1
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! solve using a system of two equations in two variables?
Four years ago, Katie was twice as old as Anne was then. In 6 years, Anne will be the same age as Katie is now. How old is each now?
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Let katie's age not be "k"; Let Anne's age now be "a"
4 yrs ago equation: k-4 = 2(a-4)
6 yrs from now eq : k = a+6
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Rearrange:
2a-k = 4
a-k = -6
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Subtract the end equation from the first to get:
a = 10 (anne's age now)
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Substitute into a-k = -6 to solve for "k":
10-k = -6
k = 16 (katie's age now)
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Cheers,
Stan H.
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