SOLUTION: How do I solve by using a system of two equations in two variables?
A duck can fly 2400 m in 10 min with the wind. Against the wind, it can fly only two thirds of this distance
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A duck can fly 2400 m in 10 min with the wind. Against the wind, it can fly only two thirds of this distance
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Question 141089This question is from textbook Prentice hall algebra 1
: How do I solve by using a system of two equations in two variables?
A duck can fly 2400 m in 10 min with the wind. Against the wind, it can fly only two thirds of this distance in 10 min. How fast could the duck fly in still air? What is the rate of the wind? This question is from textbook Prentice hall algebra 1
You can put this solution on YOUR website! How do I solve by using a system of two equations in two variables?
A duck can fly 2400 m in 10 min with the wind. Against the wind, it can fly only two thirds of this distance in 10 min. How fast could the duck fly in still air? What is the rate of the wind?
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Let still wind rate be "s"; Let wind rate to "w".
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EQUATIONS:
s + w = 2400 meter/10 min = 240 meters / minute
s - w = (2/3)2400 meter/10min = 160 meters/ minute
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2s = 400 meters/min
s = 200 meters/min (duck in still air speed)
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Substitute to solve for "w":
200 + w = 240
w = 40 meters/ min (wind speed)
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Cheers,
Stan H.
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