Question 141088: 3x+4y=17
6y-2x=-20
Im stuck.
Found 2 solutions by jim_thompson5910, rapaljer: Answer by jim_thompson5910(35256) (Show Source):
You can put this solution on YOUR website!
Start with the second equation
Rearrange the terms
So now we have the system of equations:
Let's use elimination to solve this system
Now in order to solve this system by using elimination/addition, we need to solve (or isolate) one variable. I'm going to solve for y.
In order to solve for one variable, we must eliminate the other variable. So if we wanted to solve for , we would have to eliminate (or vice versa).
So lets eliminate . In order to do that, we need to have both coefficients that are equal in magnitude but have opposite signs (for instance 2 and -2 are equal in magnitude but have opposite signs). This way they will add to zero. By adding to zero, they can be eliminated.
So to make the coefficients equal in magnitude but opposite in sign, we need to multiply both coefficients by some number to get them to an common number. So if we wanted to get and to some equal number, we could try to get them to the LCM.
Since the LCM of and is , we need to multiply both sides of the top equation by and multiply both sides of the bottom equation by like this:
Multiply the top equation (both sides) by 
Multiply the bottom equation (both sides) by
Distribute and multiply

Now add the equations together. In order to add 2 equations, group like terms and combine them
Combine like terms and simplify
Notice how the x terms cancel out
Simplify
Divide both sides by to isolate y
Reduce
Now plug this answer into the top equation to solve for x
Start with the first equation
Plug in
Multiply
Add 4 to both sides
Combine like terms on the right side
Divide both sides by 3 to isolate x
Divide
So our answer is
and
which also looks like
Now let's graph the two equations (if you need help with graphing, check out this solver)
From the graph, we can see that the two equations intersect at . This visually verifies our answer.
graph of (red) and (green) and the intersection of the lines (blue circle).
Answer by rapaljer(4671) (Show Source):
You can put this solution on YOUR website! 3x+4y=17
6y-2x=-20
Rewrite this as
3x+4y=17
-2x + 6y=-20
To eliminate the x terms, you need to find a "common number" between the x coefficients. This would be 6. Multiply both sides of the first equation by 2 and the second equation by 3, and the x terms will subtract out!
2(3x+4y)=2(17)
3(-2x + 6y)=3(-20)
6x+8y=34
-6x +18y = -60
26y = -26
y=-1
Solve for x by substituting the value of y =-1 into the first equation:
3x+4y=17
3x+4(-1) = 17
3x -4=17
3x=21
x=7
Check by substituting both values into the second equation:
-2x + 6y=-20
-2(7) + 6(-1) =-20
-14-6=-20
This checks!!
For additional explanation on the topic of Systems of Equatiaons, see my own website by clicking on my tutor name "rapaljer" anywhere in algebra.com. Take the second link on my homepage which is "Basic, Intermediate, and College Algebra: One Step at a Time", click on "Basic Algebra" and look for Chapter 4, Section 4.07. This is an explanation written for folks who didn't get math the first time!!
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