SOLUTION: How do I solve using a system of two equations in two variables?
When Lucy swims with the current, she swims 18km in 2 hours. Against the current, she can swim only 14km in the
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When Lucy swims with the current, she swims 18km in 2 hours. Against the current, she can swim only 14km in the
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Question 141076This question is from textbook Prentice Hall Algebra 1
: How do I solve using a system of two equations in two variables?
When Lucy swims with the current, she swims 18km in 2 hours. Against the current, she can swim only 14km in the same time. How fast can Lucy swim in still water? What is the rate of the current? This question is from textbook Prentice Hall Algebra 1
You can put this solution on YOUR website! How do I solve using a system of two equations in two variables?
When Lucy swims with the current, she swims 18km in 2 hours. Against the current, she can swim only 14km in the same time. How fast can Lucy swim in still water? What is the rate of the current?
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Let her still water speed be "s"; Let current speed be "c".
EQUATIONS:
s + c = 18 km/2 hrs
s - c = 14 km/2 hrs
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I think you can solve for s and c.
Cheers,
Stan H.
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