SOLUTION: Tutor please help and would you please solve by substitution method.
x = 1/8y - 1
y = 1/4x + 39
I would be very grateful for your help.
Thank you
Question 137403This question is from textbook
: Tutor please help and would you please solve by substitution method.
x = 1/8y - 1
y = 1/4x + 39
I would be very grateful for your help.
Thank you This question is from textbook
You can put this solution on YOUR website! solve by substitution method.
x = 1/8y - 1
y = 1/4x + 39
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y = (1/4)[(1/8)y - 1] + 39
y = (1/32)y - (1/4) + 39
(31/32)y = (155/4)
(31/8)y = 155
(1/8)y = 31
y = 248
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Substitute into x = (1/8)y -1 to solve for "x"
x = (1/8)248 -1
x = 32
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Final Answer: x = 32, y = 248
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Cheers,
Stan H.
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