Question 133406: Okay could I please get help with this one. I've to a certain point and have gotten stuck. I need to find the equation of a line that passes through points
(0,2) and (4,4)
This is what I have done so far.
first to find the slope I used m = 4 -2/4-0
The intercept would be 2/4
now for the point slope of the line I used y-2 = 2/4 (x + 0)
y -2 = 2/4x + 2/4
y-2 + 2 = 2/4x + 2/4 + 2
y = 2/4x + this is where I have gotten lost
I would appreciate the help
Answer by jim_thompson5910(35256)   (Show Source):
You can put this solution on YOUR website! First lets find the slope through the points ( , ) and ( ,)
 Start with the slope formula (note: ) is the first point (,) and ) is the second point (,))
 Plug in  , , , (these are the coordinates of given points)
 Subtract the terms in the numerator  to get . Subtract the terms in the denominator  to get
 Reduce
So the slope is
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Now let's use the point-slope formula to find the equation of the line:
------Point-Slope Formula------
 where  is the slope, and ) is one of the given points
So lets use the Point-Slope Formula to find the equation of the line
 Plug in , , and (these values are given)
 Distribute 
 Multiply and to get  . Now reduce to get
 Add to both sides to isolate y
 Combine like terms and to get
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Answer:
So the equation of the line which goes through the points (,) and (,) is:
The equation is now in  form (which is slope-intercept form) where the slope is and the y-intercept is 
Notice if we graph the equation and plot the points (,) and (,), we get this: (note: if you need help with graphing, check out this solver)
 Graph of through the points (,) and (,)
Notice how the two points lie on the line. This graphically verifies our answer.
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