Question 129270: I am trying to learn the substitution method.
I do not understand the steps.
Here is my problem;
2x-3y = 12
x = 4y + 1 Found 2 solutions by brikay0299, jim_thompson5910:Answer by brikay0299(3) (Show Source):
You can put this solution on YOUR website! 2x-3y=12 x=4y+1 you would add what x equals in the place of x and solve
2*4y+1-3y=12 take all the numbers with letters next to it and add,subtract,divide,or multiply the numbers 2*1y+1=12 then drop the one and it just becomes y now add the numbers 2 and 1 that would become 3y=12 now divide each side by 3 to get rid of the 3 next to y cause dividing number will cause multiplication to cancel it out come up with answer 4
check answer
2x-3y=12 3*4=12
2*4y+1-3y=12
2*y+1=12
3y=12
3y/3=12/3
y=4
Plug in into the first equation. In other words, replace each with . Notice we've eliminated the variables. So we now have a simple equation with one unknown.
Distribute
Combine like terms on the left side
Subtract 2 from both sides
Combine like terms on the right side
Divide both sides by 5 to isolate y
Divide
Now that we know that , we can plug this into to find
Substitute for each
Simplify
So our answer is and which also looks like
Notice if we graph the two equations, we can see that their intersection is at . So this verifies our answer.
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