SOLUTION: Graph the system of 5x – 2y < 10, x + 2y > -2, x – y > -4 Where do I begin and how do I graph? I have been having a difficult time with graphing.

Algebra ->  Coordinate Systems and Linear Equations  -> Lessons -> SOLUTION: Graph the system of 5x – 2y < 10, x + 2y > -2, x – y > -4 Where do I begin and how do I graph? I have been having a difficult time with graphing.       Log On


   

Question 127882: Graph the system of 5x – 2y < 10, x + 2y > -2, x – y > -4
Where do I begin and how do I graph? I have been having a difficult time with graphing.

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Graph the system of
5x – 2y < 10
x + 2y > -2
x – y > -4
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Solve each for "Y":
y > (5/2)x - 5
y > (-1/2)x - 1
y < x + 4
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Graph the boundary for each of these inequalities
by graphing each EQUALITY:
y = (5/2)x - 5
y = (-1/2)x - 1
y = x +4
--------------------
graph%28400%2C300%2C-10%2C15%2C-10%2C15%2C%285%2F2%29x-5%2C%28-1%2F2%29x-1%2Cx%2B4%29
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Shade the half-plane above (5/2)x-5
Shade the half-plane above (-1/2)x-1
Shade the half-plane below x+4
-----------------------------
The intersection of these half-planes is the solution set for
the system of three inequalities.
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Cheers,
Stan H.