SOLUTION: how do you show the linear graph for y<6 and y>3

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Question 125135This question is from textbook algebra 1
: how do you show the linear graph for y<6 and y>3 This question is from textbook algebra 1

Found 2 solutions by ilana, MathLover1:
Answer by ilana(307) About Me  (Show Source):
You can put this solution on YOUR website!
You make a dotted horizontal line at y=6 and a dotted horizontal line at y=3. Then you shade in between the two lines since that is the area less than 6 and more than 3.

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

if y%3C6 then solution will be interval (-infinity, 6)
if +y+%3E+3 then solution will be interval (3, infinity)



Solved by pluggable solver: Solve the System of Equations by Graphing



Start with the given system of equations:


0x%2By=6

0x%2By=3





In order to graph these equations, we need to solve for y for each equation.




So let's solve for y on the first equation


0x%2By=6 Start with the given equation



1y=6-0x Subtract 0+x from both sides



1y=-0x%2B6 Rearrange the equation



y=%28-0x%2B6%29%2F%281%29 Divide both sides by 1



y=%28-0%2F1%29x%2B%286%29%2F%281%29 Break up the fraction



y=0x%2B6 Reduce



Now lets graph y=0x%2B6 (note: if you need help with graphing, check out this solver)



+graph%28+600%2C+600%2C+-10%2C+10%2C+-10%2C+10%2C+0x%2B6%29+ Graph of y=0x%2B6




So let's solve for y on the second equation


0x%2By=3 Start with the given equation



1y=3-0x Subtract 0+x from both sides



1y=-0x%2B3 Rearrange the equation



y=%28-0x%2B3%29%2F%281%29 Divide both sides by 1



y=%28-0%2F1%29x%2B%283%29%2F%281%29 Break up the fraction



y=0x%2B3 Reduce





Now lets add the graph of y=0x%2B3 to our first plot to get:


+graph%28+600%2C+600%2C+-10%2C+10%2C+-10%2C+10%2C+0x%2B6%2C0x%2B3%29+ Graph of y=0x%2B6(red) and y=0x%2B3(green)


From the graph, we can see that the two lines are parallel and will never intersect. So there are no solutions and the system is inconsistent.