SOLUTION: It is 76°F at the 5,500-foot level of a mountain and 41°F at the 9,000-foot level of the mountain. Use the elevation as the e-value. For example, at the elevation 7000 feet, u

Algebra ->  Coordinate Systems and Linear Equations  -> Lessons -> SOLUTION: It is 76°F at the 5,500-foot level of a mountain and 41°F at the 9,000-foot level of the mountain. Use the elevation as the e-value. For example, at the elevation 7000 feet, u      Log On


   

Question 1204947: It is 76°F at the 5,500-foot level of a mountain and 41°F at the 9,000-foot level of the mountain.
Use the elevation as the e-value. For example, at the elevation 7000 feet, use e=7000.
a. Write an equation to find the temperature (T) at an elevation (e) on the mountain.
Round decimals to 4 places.
b. Using your equation from part (a), predict the temperature at an elevation of 16,200 feet.
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
It is 76°F at the 5,500-foot level of a mountain and 41°F at the 9,000-foot level of the mountain.
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The altitude change is 3500 feet and the temperature change is -35 degs.
---> -1 deg/100 feet
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Use the elevation as the e-value. For example, at the elevation 7000 feet, use e=7000.
a. Write an equation to find the temperature (T) at an elevation (e) on the mountain.
Round decimals to 4 places.
T+=+76+-+%28e-3500%29%2F100 degs F
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b. Using your equation from part (a), predict the temperature at an elevation of 16,200 feet.
T+=+76+-+%2816200+-+3500%29%2F100
T = -51 degs F
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This assumes the relation between altitude and temp is linear, but it is not.