SOLUTION: The school football team held a car wash to raise money. They washed cars for $4 each and vans for $6 each. They washed a total of 61 vehicles and raised $278. How many of each
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Question 1203110: The school football team held a car wash to raise money. They washed cars for $4 each and vans for $6 each. They washed a total of 61 vehicles and raised $278. How many of each type of vehicle did they wash? Found 3 solutions by math_tutor2020, ikleyn, greenestamps:Answer by math_tutor2020(3817) (Show Source):
You can put this solution on YOUR website! .
The school football team held a car wash to raise money.
They washed cars for $4 each and vans for $6 each.
They washed a total of 61 vehicles and raised $278.
How many of each type of vehicle did they wash?
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x washed vans and (61-x) washed cars.
Total money equation is
6x + 4*(61-x) = 278.
Simplify and find x
6x + 244 - 4x = 278,
6x - 4x = 278 - 244
2x = 34
x = 34/2 = 17.
ANSWER. They washed 17 vans and 61 - 17 = 44 cars.
CHECK. 6*17 + 4*44 = 278 dollars, total money earned. ! correct !
Look at the responses from the other two tutors who provided formal algebraic solutions to see that it is almost always the case that a tiny bit of extra work at the beginning to set the problem up using only one variable results in a faster and easier path to the solution.
And if formal algebra is not required, this is a very common type of problem that can be solved quickly and easily using logical reasoning and simple arithmetic:
If all 61 vehicles had been cars, the total raised would have been 61($4) = $244.
The actual total was $278, which is $34 more.
The difference between the cost for a car and the cost for a van was $2.
Therefore, the number of vans was $34/$2 = 17.