Question 1201079: The Royal Fruit Company produces two types of fruit drinks. The first type is 30% pure fruit juice, and the second type is 70% pure fruit juice. The company is attempting to produce a fruit drink that contains 60% pure fruit juice. How many pints of each of the two existing types of drink must be used to make 80 pints of a mixture that is 60% pure fruit juice?
Found 3 solutions by mananth, josgarithmetic, greenestamps: Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website!
Juice 1 30% ---------------- x pints
juice 2 70% ---------------- 80 - x pints
Mixture 60.00% ---------------- 80
Juice 1 0.3 ---------------- x pints
juice 2 0.7 ---------------- 80 - x pints
Mixture 0.60 ---------------- 80
0.3 x + 0.7 ( 80 - x ) = 80.00 * 0.60
0.3 x + 56 - 0.7 x = 48.00
0.3 x - 0.7 x = 48 - 56
-0.4 x = -8
/ -0.4
x = 20 pints 30.00% Juice 1
60 pints 70.00% juice 2
Answer by josgarithmetic(39617) (Show Source): Answer by greenestamps(13200) (Show Source):
You can put this solution on YOUR website!
Tutor @mananth has provided a good standard formal algebraic solution. You can use that as a good example of how the problem can be solved.
Or, if you like to torture yourself, you can also use the rather absurd method tutor @josgarthmetic loves to show on this kind of problem -- with all those variables.
Finally, if a formal algebraic solution is not required, this problem can be solved in a few seconds informally:
The target of 60% is 3/4 of the way from 30% to 70%; therefore, 3/4 of the mixture is the 70% fruit juice.
ANSWER: 3/4 of 80 pints, or 60 pints, is the 70% fruit juice; the other 20 pints is the 30% fruit juice.
|
|
|