SOLUTION: Write an equation for a line perpendicular to 3y+6x=−6 and passing through the point (-4,-6)

Algebra ->  Coordinate Systems and Linear Equations  -> Lessons -> SOLUTION: Write an equation for a line perpendicular to 3y+6x=−6 and passing through the point (-4,-6)      Log On


   

Question 1195347: Write an equation for a line perpendicular to 3y+6x=−6 and passing through the point (-4,-6)
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

an equation for a line perpendicular to 3y%2B6x=-6 and passing through the point (-4,-6)
perpendicular lines have a slopes negative reciprocal to each other
so, write the equation of given line in slope intercept form y=mx%2Bb

3y%2B6x=-6
3y=-6x-6
y=-6x%2F3-6%2F3
y=-2x-2 => slope is m=-2

then a slope of the perpendicular line will be m=-1%2F%28-2%29=1%2F2
now we have a slope and one point which is enough to find equation of the perpendicular line using point slope formula

y-y%5B1%5D=m%28x-x%5B1%5D%29.........plug in m=1%2F2 and point (-4,-6)

y-%28-6%29=%281%2F2%29%28x-%28-4%29%29

y%2B6=%281%2F2%29%28x%2B4%29

y%2B6=%281%2F2%29x%2B2

y=%281%2F2%29x%2B2-6

y=%281%2F2%29x-4 -> your line