SOLUTION: Five years from now, Jabin's grandmother will be 3 times as old as Jabin. The sum of the squares of their ages in 5 years is 8410. what is Jabin's present age?
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-> SOLUTION: Five years from now, Jabin's grandmother will be 3 times as old as Jabin. The sum of the squares of their ages in 5 years is 8410. what is Jabin's present age?
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Question 1185055: Five years from now, Jabin's grandmother will be 3 times as old as Jabin. The sum of the squares of their ages in 5 years is 8410. what is Jabin's present age?
Can you help me please... Found 2 solutions by josgarithmetic, ikleyn:Answer by josgarithmetic(39617) (Show Source):
You can put this solution on YOUR website! .
Five years from now, Jabin's grandmother will be 3 times as old as Jabin.
The sum of the squares of their ages in 5 years is 8410. what is Jabin's present age?
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This problem has a simple and elegant solution. All you need is to look
at the problem from the right point of view . . .
Let x be the Jabin's age in 5 years from now.
Then the grandmother's age in 5 years from now will be 3x, according to the condition.
Now we write equation for x as we read the problem
x^2 + (3x)^2 = 8410.
Simplify and find x
x^2 + 9x^2 = 8410
10x^2 = 8410
x^2 = 841
x = = 29 is the Jabin's age in 5 years from now.
ANSWER. This year, Jabin is 29-5 = 24 years old.
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