SOLUTION: Solve the system by addition. 3x + y = –1 9x + 3y = –3

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Question 117945: Solve the system by addition.
3x + y = –1
9x + 3y = –3

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

Solved by pluggable solver: Solving a System of Linear Equations by Elimination/Addition


Lets start with the given system of linear equations

3%2Ax%2B1%2Ay=-1
9%2Ax%2B3%2Ay=-3

In order to solve for one variable, we must eliminate the other variable. So if we wanted to solve for y, we would have to eliminate x (or vice versa).

So lets eliminate x. In order to do that, we need to have both x coefficients that are equal but have opposite signs (for instance 2 and -2 are equal but have opposite signs). This way they will add to zero.

So to make the x coefficients equal but opposite, we need to multiply both x coefficients by some number to get them to an equal number. So if we wanted to get 3 and 9 to some equal number, we could try to get them to the LCM.

Since the LCM of 3 and 9 is 9, we need to multiply both sides of the top equation by 3 and multiply both sides of the bottom equation by -1 like this:

3%2A%283%2Ax%2B1%2Ay%29=%28-1%29%2A3 Multiply the top equation (both sides) by 3
-1%2A%289%2Ax%2B3%2Ay%29=%28-3%29%2A-1 Multiply the bottom equation (both sides) by -1


So after multiplying we get this:
9%2Ax%2B3%2Ay=-3
-9%2Ax-3%2Ay=3

Notice how 9 and -9 add to zero, 3 and -3 add to zero, -3 and 3 and to zero (ie 9%2B-9=0) 3%2B-3=0, and -3%2B3=0)


So we're left with

0=0


which means any x or y value will satisfy the system of equations. So there are an infinite number of solutions


So this system is dependent