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𝑝1 + 3𝑝2 + 3𝑝3 = 32 (1)
𝑝1 + 4𝑝2 + 3𝑝3 = 37 (2)
𝑝1 + 3𝑝2 + 4𝑝3 = 35 (3)
From equation (3), subtract equation (1). You will get
p3 = 35 - 32 = 3. (4)
Next, from equation (2), subtract equation (1). You will get
p2 = 37 - 32 = 5.
Sunbstitute the found values p2= 5, p3 = 3 into equation (1). You will get
p1 + 3*5 + 3*3 = 32
which implies
p1 = 32 - 3*5 - 3*3 = 8.
ANSWER. p1= 8, p2= 5, p3= 3.
Solved.