SOLUTION: Write a system of two equations in two variables to solve the problem. On a mother's 23-mile commute to work, she drops her daughter off at a child care center. The first part o

Algebra ->  Coordinate Systems and Linear Equations  -> Lessons -> SOLUTION: Write a system of two equations in two variables to solve the problem. On a mother's 23-mile commute to work, she drops her daughter off at a child care center. The first part o      Log On


   



Question 1153846: Write a system of two equations in two variables to solve the problem.
On a mother's 23-mile commute to work, she drops her daughter off at a child care center. The first part of the trip is 5 miles less than the second part. How long is each part of her morning commute?
first part
mi
second part
m

Found 2 solutions by MathLover1, ikleyn:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

On a mother's 23-mile commute to work, she drops her daughter off at a child care center.
23mil
The first part of the tripx is 5 miles less than the second y part.
x=y-5mi.......eq.1
total of her trip:
x%2By=23mi.......eq.2
substitute x from eq.1 in eq.2
y-5mi%2By=23mi.......eq.2
2y=23mi%2B5mi
2y=28mi
y=14mi
go to
x=y-5mi.......eq.1, plug in y
x=14mi-5mi
x=9mi

How long is each part of her morning commute?
first part is 9mi
second part is 14mi


Answer by ikleyn(52787) About Me  (Show Source):
You can put this solution on YOUR website!
.

Let x be the first part distance, in miles; let y be the second part distance.


Then your system of equations can be written in this form


    x + y = 23     (1)     (miles total)

    x = y - 5      (2)     (The first part of the trip is 5 miles less than the second part) 



or in this form


    x + y = 23     (1)     (miles total)

    x - y  = 5     (2)     (The first part of the trip is 5 miles less than the second part) 


Both forms are equivalent.


First form is just ready for the solution by the Substitution method.


While the second form is just ready for the solution by the Elimination method.


You may use ANY of these two forms and/or ANY of these two possible solution methods.

Enjoy Math (!)