SOLUTION: Ina Crespo rowed 13.5 miles down the Habashabee River in 1.5 hours, but the return trip took her 4.5 hours. Find the rate Ina rows in still water and the rate of the current. Le
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-> SOLUTION: Ina Crespo rowed 13.5 miles down the Habashabee River in 1.5 hours, but the return trip took her 4.5 hours. Find the rate Ina rows in still water and the rate of the current. Le
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Question 1141755: Ina Crespo rowed 13.5 miles down the Habashabee River in 1.5 hours, but the return trip took her 4.5 hours. Find the rate Ina rows in still water and the rate of the current. Let x represent the rate Ina can row in still water and let y represent the rate of the current.
Let x represent the rate Ina can row in still water (in miles per hour, mph).
Let y represent the rate of the current.
The effective speed going downstream is
= = 9 mph.
The effective speed going downstream is the SUM of the Ina' speed in still water and the rate of the current.
It gives you your first equation
x + y = 9. (1)
The effective speed going upstream is
= = 3 mph.
The effective speed going upstream is the DIFFERENCE of the Ina' speed in still water and the rate of the current. It gives you your second equation
x - y = 3. (2)
Thus you have this system of two equations in 2 unknowns
x + y = 9, (1) and
x - y = 3. (2)
Add the two equations. You will get
2x = 9 + 3 = 12 ====> u = = 6 mph.
So, you just found the Ina' speed in still water. It is 6 miles per hour.
Then from the equation (1) you get y = 9 - 6 = 3 mph is the current rate.
Answer. The Ina' speed in still water is 6 mph.
The current rate is 3 mph.