Question 1139590: What is the result of isolating x^2 in the equation? (x+1)^2+(y-8)^2=9
A.x^2 = -y^2 - 2x + 16y - 56
B.x^2=y^2+56
C.x^2=y^2+2x+16y+56
D.x^2=-y^2-56
Answer by Theo(13342)   (Show Source):
You can put this solution on YOUR website! start with (x+1)^2 + (y-8)^2 = 9
simplify to get x^2 + 2x + 1 + y^2 - 16y + 64 = 9
combine like terms to get x^2 + 2x + y^2 - 16y + 65 = 9
subtract 65 from both sides of the equation to get x^2 + 2x + y^2 - 16y = -56
subtract 2x from both sides of the equation and subtract y^2 from both sides of the equation and add 16y to both sides of the equation to get:
x^2 = -56 - 2x - y^2 + 16y
rearrange the terms in descending order of degree, with the x variable shown before the y variable when the degree is the same, to get:
x^2 = -y^2 - 2x + 16y - 56
that looks a lot like selection A, which is:
x^2 = -y^2 - 2x + 16y - 56
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