Question 1129198: Solve the system of equations:
Y=2x2+3
Y=x+2
Enter one point as (x,y)
Enter teo points as (x,y),(x,y)
Enter"no solution" as DNE. Answer by ikleyn(52790) (Show Source):
y = 2x^2 + 3
y = x + 2
Left sides are identical - hence, right sides are equal:
2x^2 + 3 = x + 2 ====>
2x^2 -x + 1 = 0.
The discriminant = b^2 - 4ac = (-1)^2 - 4*2*1 = 1 - 8 = -7 ====>
There is no real solution.
= = .
Answer. This system HAS NO real solution/solutions.
It has two distinct solution in complex numbers (x,y) = (,} and (x,y) = (,).
Solved and explained.
You can simplify these complex number solutions, if you need (if you need to have them, at all).
