SOLUTION: 2 LINEAR EQUATIONS IN 2 UNKNOWNS or SIMULTANEOUS LINEAR EQUATIONS IN 2 UKNOWNS if twice the length of a rectangle is increased by three times the width, the sum is 48 feet. The

Algebra ->  Coordinate Systems and Linear Equations  -> Lessons -> SOLUTION: 2 LINEAR EQUATIONS IN 2 UNKNOWNS or SIMULTANEOUS LINEAR EQUATIONS IN 2 UKNOWNS if twice the length of a rectangle is increased by three times the width, the sum is 48 feet. The       Log On


   



Question 1122282: 2 LINEAR EQUATIONS IN 2 UNKNOWNS or SIMULTANEOUS LINEAR EQUATIONS IN 2 UKNOWNS
if twice the length of a rectangle is increased by three times the width, the sum is 48 feet. The perimeter is 40 feet what are the dimensions of the rectangle?

Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


(1) Twice the length of a rectangle increased by three times the width is 48 feet: 2w+3l = 48

(2) The perimeter is 40 feet: 2w+2l = 40

Either by looking at those equations, or by thinking logically about the given information, the difference between those two measurements is the width of the rectangle.

Finishing the problem from there should be easy.