SOLUTION: I am working on the following problem and hope I did it right. Adult tickets for a play cost $15 and child tickets cost $6. If there were 33 people at a performatnce and the thea

Algebra ->  Coordinate Systems and Linear Equations  -> Lessons -> SOLUTION: I am working on the following problem and hope I did it right. Adult tickets for a play cost $15 and child tickets cost $6. If there were 33 people at a performatnce and the thea      Log On


   



Question 111869: I am working on the following problem and hope I did it right.
Adult tickets for a play cost $15 and child tickets cost $6. If there were 33 people at a performatnce and the theater collected $360 from ticket sales, how many children attended the play?
Let X= Adult tix
Let Y= Child tix
1x+1y=33
15x+6y=360
Then I had to multiply the first equation by 15.
(15)(1x+1y) = 33(15)
15x+15y= 495
Then I had to multiply the other equation by -1
(-1)(15x+6y) =360(-1)
-15x-6y=-360
Then I had to add both equations together.
15x+15y=495
-15x-6y=-360 the result was
9y=135
I divided both sides by 9
and came up with y=15.
Is that correct?
I tried to check my work by inputting
1x+1(15)=33
1x+15=33
then subtracted 15 from both sides and came up with x=18.
When I tried to check my work
15(15) +6(18)this is supposed to =360 and I don't think that came out right.
What did I do wrong?
Thank you.
Tracy

Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
YOU WERE OK UNTIL YOU MIXED UP THE X=18 & Y=15
15*18+6*15=360
279+90=360
360=360