SOLUTION: HELP HELP HELP solve by addition if a unique solution does not exist state whether the system is inconsistent or dependent. -3x+y=8 3x-2y=-10 thanks so much

Algebra ->  Coordinate Systems and Linear Equations  -> Lessons -> SOLUTION: HELP HELP HELP solve by addition if a unique solution does not exist state whether the system is inconsistent or dependent. -3x+y=8 3x-2y=-10 thanks so much      Log On


   



Question 110900: HELP HELP HELP
solve by addition if a unique solution does not exist state whether the system is inconsistent or dependent.
-3x+y=8
3x-2y=-10
thanks so much

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Solved by pluggable solver: Solving a System of Linear Equations by Elimination/Addition


Lets start with the given system of linear equations

-3%2Ax%2B1%2Ay=8
3%2Ax-2%2Ay=-10

In order to solve for one variable, we must eliminate the other variable. So if we wanted to solve for y, we would have to eliminate x (or vice versa).

So lets eliminate x. In order to do that, we need to have both x coefficients that are equal but have opposite signs (for instance 2 and -2 are equal but have opposite signs). This way they will add to zero.

So to make the x coefficients equal but opposite, we need to multiply both x coefficients by some number to get them to an equal number. So if we wanted to get -3 and 3 to some equal number, we could try to get them to the LCM.

Since the LCM of -3 and 3 is -3, we need to multiply both sides of the top equation by 1 and multiply both sides of the bottom equation by 1 like this:

1%2A%28-3%2Ax%2B1%2Ay%29=%288%29%2A1 Multiply the top equation (both sides) by 1
1%2A%283%2Ax-2%2Ay%29=%28-10%29%2A1 Multiply the bottom equation (both sides) by 1


So after multiplying we get this:
-3%2Ax%2B1%2Ay=8
3%2Ax-2%2Ay=-10

Notice how -3 and 3 add to zero (ie -3%2B3=0)


Now add the equations together. In order to add 2 equations, group like terms and combine them
%28-3%2Ax%2B3%2Ax%29%2B%281%2Ay-2%2Ay%29=8-10

%28-3%2B3%29%2Ax%2B%281-2%29y=8-10

cross%28-3%2B3%29%2Ax%2B%281-2%29%2Ay=8-10 Notice the x coefficients add to zero and cancel out. This means we've eliminated x altogether.



So after adding and canceling out the x terms we're left with:

-1%2Ay=-2

y=-2%2F-1 Divide both sides by -1 to solve for y



y=2 Reduce


Now plug this answer into the top equation -3%2Ax%2B1%2Ay=8 to solve for x

-3%2Ax%2B1%282%29=8 Plug in y=2


-3%2Ax%2B2=8 Multiply



-3%2Ax=8-2 Subtract 2 from both sides

-3%2Ax=6 Combine the terms on the right side

cross%28%281%2F-3%29%28-3%29%29%2Ax=%286%29%281%2F-3%29 Multiply both sides by 1%2F-3. This will cancel out -3 on the left side.


x=-2 Multiply the terms on the right side


So our answer is

x=-2, y=2

which also looks like

(-2, 2)

Notice if we graph the equations (if you need help with graphing, check out this solver)

-3%2Ax%2B1%2Ay=8
3%2Ax-2%2Ay=-10

we get



graph of -3%2Ax%2B1%2Ay=8 (red) 3%2Ax-2%2Ay=-10 (green) (hint: you may have to solve for y to graph these) and the intersection of the lines (blue circle).


and we can see that the two equations intersect at (-2,2). This verifies our answer.