SOLUTION: A chemist needs to make 200L of a 62% solution by mixing together an 80% solution with a 30% solution. How much of each solution should she use?

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Question 1106184: A chemist needs to make 200L of a 62% solution by mixing together an 80% solution with a 30% solution. How much of each solution should she use?
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
x Liters of the 80% material

30%28200-x%29%2B80x=62%2A200

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3%28200-x%29%2B8x=62%2A20
600-3x%2B8x=62%2A20
5x=62%2A20-600
x=62%2A4-120
highlight%28x=128%2ALiters%29--------of the 80% material
highlight%2872%2Aliters%29---------of the 30% material