SOLUTION: the length of a rectangle is 10ft less than twice the width. if the perimeter is 178 ft, find the length and width.

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Question 1103663: the length of a rectangle is 10ft less than twice the width. if the perimeter is 178 ft, find the length and width.
Answer by ikleyn(52784) About Me  (Show Source):
You can put this solution on YOUR website!
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(1)    L = 2W-10

(2)    L +      W +  L     + W = 178

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      (2W-10) + W + (2W-10) + W = 178  ====>

      6W - 20 = 178  ====>  6W = 178 + 20 = 198  ====>  W = 198%2F6 = 33.


Amswer.  W = 33 ft,  L = 2W-10 = 2*33-10 = 56 ft.