SOLUTION: What is the smallest value of x that satisfies the equation 8x^2 - 38x + 35 = 0? Express your answer as a decimal.

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Question 1092140: What is the smallest value of x that satisfies the equation 8x^2 - 38x + 35 = 0? Express your answer as a decimal.
Found 2 solutions by ikleyn, greenestamps:
Answer by ikleyn(52787) About Me  (Show Source):
You can put this solution on YOUR website!
.
Solve the quadratic equation, using the quadratic formula.


Find its two  roots.


Of the two, choose smaller.


It would be your answer.

Solving quadratic equation by using the quadratic formula is a mechanical work,
IF YOU KNOW the QUADRATIC FORMULA.

It is also the necessary skill for Algebra-I students.


To learn on the quadratic formula, see the lessons
    - Introduction into Quadratic Equations
    - PROOF of quadratic formula by completing the square
in this site.



Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!

By trial and error, or whatever method you might have learned, the quadratic factors nicely.

8x%5E2+-+38x+%2B+35+=+0
%284x-5%29%282x-7%29+=+0

4x-5+=+0 or 2x-7+=+0

Which factor gives you the smaller solution? What is that smaller solution?