SOLUTION: For what negative value of k is there exactly one solution to this system of equations y=2x^2+kx+6 y=-x+4
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Question 1085952
:
For what negative value of k is there exactly one solution to this system of equations
y=2x^2+kx+6
y=-x+4
Found 2 solutions by
rapture, ikleyn
:
Answer by
rapture(86)
(
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You can
put this solution on YOUR website!
Use the discriminant b^2 - 4ac.
a = 2, b = k, c = 6
Set discriminant to 0 and solve for k.
k^2 - 4(2)(6) = 0
k^2 - 8(6) = 0
k^2 - 48 = 0
k^2 = 48
sqrt{k^2} = sqrt{48}
k = sqrt{16}sqrt{3}
k = 4sqrt{3}, k = -4sqrt{3}
The negative k value is -4sqrt{3}.
Answer by
ikleyn(52787)
(
Show Source
):
You can
put this solution on YOUR website!
.
The solution by the other tutor is
WRONG
and
IRRELEVANT
.
For correct solution see my post at this link
https://www.algebra.com/algebra/homework/coordinate/Linear-systems.faq.question.1085951.html
https://www.algebra.com/algebra/homework/coordinate/Linear-systems.faq.question.1085951.html
