SOLUTION: please help me solve this equation: x-3y=0 2x+3y+3z=18 x+2y-4z=10
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Question 108198
:
please help me solve this equation:
x-3y=0
2x+3y+3z=18
x+2y-4z=10
Answer by
scott8148(6628)
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subtracting the first equation from the third gives 5y-4z=10
subtracting 2 times the first equation from the second gives 9y+3z=18
(4/3)(9y+3z=18) ... 12y+4z=24 ... adding 5y-4z=10 gives 17y=34 ... y=2
x-(3)*(2)=0 ... x=6
6+2(2)-4z=10 ... -4z=0 ... z=0