Question 1075365: A child wanders slowly down a circular staircase from the top of a tower. With x,y,z in feet and the origin at the base of the tower, her position t minutes from the start is given by
x=15cost,y=15sint,z=120−5t.
t.
(a) How tall is the tower?
height =
ft
(b) When does the child reach the bottom?
time =
minutes
(c) What is her speed at time tt?
speed =
ft/min
(d) What is her acceleration at time tt?
acceleration =
ft/min2
Answer by jim_thompson5910(35256)   (Show Source):
You can put this solution on YOUR website! (a)
Plug t = 0 into the z equation to get
z = 120 - 5*t
z = 120 - 5*0
z = 120 - 0
z = 120
This means that when the time is t = 0 minutes, they are at z = 120.
The tower is 120 feet tall.
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(b)
The child will reach the bottom when z = 0
Plug z = 0 into the z equation and solve for t
z = 120 - 5*t
0 = 120 - 5*t
0 + 5*t = 120 - 5*t + 5*t
5*t = 120
5*t/5 = 120/5
t = 24
The child will reach the bottom at t = 24 minutes
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(c)
Unfortunately I don't have enough information to answer this problem. You wrote "tt" but didn't write any values after that. Please update the problem. Thank you.
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(d)
As in part (c), the same issue happens with this part as well. There isn't enough information. Please update.
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