Question 1075059: The value of K for which the system of linear equations
2x+y+2=0
X+ky+2z=0
X+y+2=0 Found 2 solutions by Alan3354, KMST:Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! Typo suspected.
Did you need to know the values of k
that caused the system to have one solution?
As posted, the system has one solution for each value of k.
There is no value of k that causes a different result.
If your first equation was really ,
and your last equation was really ,
subtracting the last one from the first one,
you get .
Substituting that value for in either equation,
you get ---> .
Then, substituting in the second equation
the values found for and ,
you get ---> .