SOLUTION: The value of K for which the system of linear equations 2x+y+2=0 X+ky+2z=0 X+y+2=0

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Question 1075059: The value of K for which the system of linear equations
2x+y+2=0
X+ky+2z=0
X+y+2=0

Found 2 solutions by Alan3354, KMST:
Answer by Alan3354(69443) About Me  (Show Source):
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
Typo suspected.
Did you need to know the values of k
that caused the system to have one solution?
As posted, the system has one solution for each value of k.
There is no value of k that causes a different result.

If your first equation was really
2x%2By%2B2=0 ,
and your last equation was really
x%2By%2B2=0 ,
subtracting the last one from the first one,
you get x=0 .
Substituting that value for x in either equation,
you get y%2B2=0 ---> y=-2 .
Then, substituting in the second equation
the values found for x and y ,
you get -2k%2B2z=0 ---> z=k .