SOLUTION: Pkease help solve this problem : One pipe an fill a tank in 5 hours less than another. Together they
can fill the tank in 5 hours. How long would it take each alone to fill the ta
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-> SOLUTION: Pkease help solve this problem : One pipe an fill a tank in 5 hours less than another. Together they
can fill the tank in 5 hours. How long would it take each alone to fill the ta
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Question 1074980: Pkease help solve this problem : One pipe an fill a tank in 5 hours less than another. Together they
can fill the tank in 5 hours. How long would it take each alone to fill the tank ? Compute the answer
to two decimal places. Found 2 solutions by josgarithmetic, ikleyn:Answer by josgarithmetic(39617) (Show Source):
Let x = time in hours for the faster pipe to fill the tank alone.
Then the time for the other pipe is (x+5) hours.
The faster pipe fills of the tank volume per hour.
The slower pipe fills of the tank volume per hour.
Working together, they fill of the tank volume per hour.
According to the condition,
= .
It is your equation to solve.
The first step is to multiply both sides by 5x*(x+5). You will get
5(x+5) + 5x = x*(x+5), or
5x + 25 + 5x = x^2 + 5x,
x^2 - 5x - 25 = 0.
= = .
= = 8.1 hours (approximately).
The second root is negative and doesn't work.
Check. = 0.2. Correct !
Answer. Faster pipe in 8.1 hours. Slower pipe in 13.1 hours.