SOLUTION: can someone please help me solve this problem? 3(x-2)-5(2x-1)>0. The greater than sign should have a _ under it.

Algebra ->  Coordinate Systems and Linear Equations  -> Lessons -> SOLUTION: can someone please help me solve this problem? 3(x-2)-5(2x-1)>0. The greater than sign should have a _ under it.      Log On


   

Question 107142: can someone please help me solve this problem? 3(x-2)-5(2x-1)>0. The greater than sign should have a _ under it.
Found 2 solutions by stanbon, edjones:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
3(x-2)-5(2x-1)>0
3x-6-10x+5 > 0
-7x-1 > 0
Add 7x to both sides to get:
7x < -1
x <-1/7
Cheers,
Stan H.

Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
3(x-2)-5(2x-1)>=0
3x-6-10x+5>=0
-7x-1>0
-7x-1+1>0+1
-7x>1
-7x/-7>1/-7
x<-1/7 reverse the inequality sign dividing or multiplying by a negative number.
Ed