SOLUTION: Find four consecutive integers, where twice the fourth integer equals to 25 less than half the third integer.

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Question 1068754: Find four consecutive integers, where twice the fourth integer equals to 25 less than half the third integer.
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
n, any integer
Four consecutive integers: n, n+1, n+2, n+3

2%28n%2B3%29=-25%2B%28n%2B2%29%2F2

4%28n%2B3%29=-50%2Bn%2B2
4n%2B12=n-48
3n=-48-12
3n=-60
highlight%28n=-20%29

The consecutive integers are -20, -19, -18, -17.