SOLUTION: For a certain value of k, the system: x + y + 3z = 10 -4x + 2y + 5z = 7 kx + z = 3 has no solutions. What is this value of k?

Algebra ->  Coordinate Systems and Linear Equations  -> Lessons -> SOLUTION: For a certain value of k, the system: x + y + 3z = 10 -4x + 2y + 5z = 7 kx + z = 3 has no solutions. What is this value of k?      Log On


   



Question 1068184: For a certain value of k, the system:
x + y + 3z = 10
-4x + 2y + 5z = 7
kx + z = 3
has no solutions. What is this value of k?

Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
USING DETERMINANTS:
Of you have learned about using matrices and determinants
to solve systems of equations,
you would know that the matrix associated with that system is
%28matrix%283%2C3%2C1%2C1%2C3%2C-4%2C2%2C5%2Ck%2C0%2C1%29%29 ,
and that the system has no solution if the determinant for that matrix is zero:
abs%28matrix%283%2C3%2C1%2C1%2C3%2C-4%2C2%2C5%2Ck%2C0%2C1%29%29=0 <--> 2%2B5k-6k%2B4=0 <--> 6-k=0 <--> highlight%28k=0%29 .

WITHOUT DETERMINANTS:
One way to solve that system would be
to make a linear combination of the first two equations that would have no term with y ,
and then try to solve the system made from the resulting equation and
kx%2Bz=3
Adding the first equation times 2
plus the second one times %28-1%29 , we get
6x%2Bz=13 .
Then you would solve the system
system%286x%2Bz=13%2Ckx%2Bz=3%29
Obviously, if highlight%28k=6%29 ,
that system (and the original system)
Would have no solution.