SOLUTION: The number of adults tickets sold, a, was eight times the number of child tickets sold, c,. Child tickets cost $2.50 each; adult tickets cost $5.00 each and last night's show broug

Algebra ->  Coordinate Systems and Linear Equations  -> Lessons -> SOLUTION: The number of adults tickets sold, a, was eight times the number of child tickets sold, c,. Child tickets cost $2.50 each; adult tickets cost $5.00 each and last night's show broug      Log On


   



Question 1063124: The number of adults tickets sold, a, was eight times the number of child tickets sold, c,. Child tickets cost $2.50 each; adult tickets cost $5.00 each and last night's show brought in $850.
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39617) About Me  (Show Source):
Answer by ikleyn(52784) About Me  (Show Source):
You can put this solution on YOUR website!
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The number of adults tickets sold, a, was eight times the number of child tickets sold, c,.
Child tickets cost $2.50 each; adult tickets cost $5.00 each and last night's show brought in $850.
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You can solve the problem mentally,  without using equations.

HINT: You can group the tickets in sets in a way each set contains  8  adult tickets and  1  child ticket.
            Then each set is worth  8*5 + 2.50 dollars = 42.50 dollars,  and the number of sets is  850%2F42.50 = 20.

Did you get the idea ?