SOLUTION: Find the maximal value of the object linction z = x + 3y; subject to constraints; y less than equal to x+1,x+y greater tha equal to 2, 2y greater than equal to x-1, as x greater t

Algebra ->  Coordinate Systems and Linear Equations  -> Lessons -> SOLUTION: Find the maximal value of the object linction z = x + 3y; subject to constraints; y less than equal to x+1,x+y greater tha equal to 2, 2y greater than equal to x-1, as x greater t      Log On


   



Question 1055922: Find the maximal value of the object linction z = x + 3y; subject to constraints; y less than equal to x+1,x+y greater tha equal to 2, 2y greater than equal to x-1, as x greater than equal to 0 and y greater than equal to 0.
Answer by ikleyn(52787) About Me  (Show Source):
You can put this solution on YOUR website!
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Find the maximal value of the object highlight%28cross%28linction%29%29 function z = x + 3y; subject to constraints; y less than equal to x+1,
x+y greater than equal to 2, 2y greater than equal to x-1, as x greater than equal to 0 and y greater than equal to 0.
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Plots y = x+1 (red), y = 2-x (green), y = %28x-1%29%2F2 (blue)

Make a sketch of the given area, or use the sketch I prepared for you.

Your area is the infinite domain in the first quadrant bounded by the red, green and blue straight lines.

The given object function HAS NO maximal value over this domain.

There are only two options:

1) EITHER the answer is NEGATIVE (no maximum),

2) OR the formulation is wrong.


There is NO other options.