SOLUTION: I have been attempting this problem and I have no clue as to where to go. I only have on problem left and I was not able to solve it for this section and was wondering if anyone co

Algebra ->  Coordinate Systems and Linear Equations  -> Lessons -> SOLUTION: I have been attempting this problem and I have no clue as to where to go. I only have on problem left and I was not able to solve it for this section and was wondering if anyone co      Log On


   

Question 1049300: I have been attempting this problem and I have no clue as to where to go. I only have on problem left and I was not able to solve it for this section and was wondering if anyone could please provide assistance on how I should go about solving this.
1.) Determine the rate of change for each equation.
3/2x - 5/4y = 15
Here is what I have attempted to do with the problem: I have subtracted the 3/2x to the other side and ended up with -5/4y = -3/2x +15 which is what I am currently stuck on. I feel like I went about this the correct way, but I could be wrong.

Found 2 solutions by MathLover1, MathTherapy:
Answer by MathLover1(20855) About Me  (Show Source):
You can put this solution on YOUR website!

%283%2F2%29x+-+%285%2F4%29y+=+15+
in y=mx%2Bb
m is your rate of change
you need to get y by itself
%283%2F2%29x+-+15+=+%285%2F4%29y+
3x%2F2+-+30%2F2+=+%285%2F4%29y+
%283x+-+30%29%2F2+=+%285%2F4%29y+
3x+-+30+=+2%285%2F4%29y+
3x+-+30+=+cross%282%29%285%2Fcross%284%292%29y+
3x+-+30+=+%285%2F2%29y+
2%2A3x+-+2%2A30+=+2%285%2F2%29y+
6x+-+60+=+5y+
6x%2F5+-+60%2F5+=+5y%2F5+
y=highlight%28%286%2F5%29%29x+-+12+
so,the rate of change is highlight%286%2F5%29+



Answer by MathTherapy(10836) About Me  (Show Source):
You can put this solution on YOUR website!
I have been attempting this problem and I have no clue as to where to go. I only have on problem left and I was not able to
solve it for this section and was wondering if anyone could please provide assistance on how I should go about solving this.

1.) Determine the rate of change for each equation.

3/2x - 5/4y = 15

Here is what I have attempted to do with the problem: I have subtracted the 3/2x to the other side and ended up with -5/4y =
-3/2x +15 which is what I am currently stuck on. I feel like I went about this the correct way, but I could be wrong.
***************
%283%2F2%29x+-+%285%2F4%29y+=+15

-5/4y = -3/2x +15 "....what I am currently stuck on.
You could continue by DIVIDING each side of the equation by the coefficient of y, -+5%2F4, or MULTIPLYING by its RECIPROCAL, -+4%2F5. 
      %28-+5%2F4%29y%28-+4%2F5%29+=+%28-+3%2F2%29x+%2A+%28-+4%2F5%29+%2B+15+%2A+%28-+4%2F5%29 ------ Multiplying each side by -+4%2F5

                         y+=+%286%2F5%29x+-+12, wherein, m, or 6%2F5 is your required RATE of CHANGE!

However, it's less complex, less time-consuming and less of a headache, in this author's opinion, when you CLEAR/GET rid of the
fractions, first and foremost, as follows: %283%2F2%29x+-+%285%2F4%29y+=+15
                                                                                 6x - 5y = 60 ---- Multiplying by LCD, 4
                                                                                      - 5y = - 6x + 60
                                                                            %28%28-+5%29%2F%28-+5%29%29y+=+%28%28-+6%29%2F%28-+5%29%29x+%2B+60%2F%28-+5%29 ---- Dividing each side by - 5
                                                                                         y+=+%286%2F5%29x+-+12, wherein, m, or 6%2F5 is your required RATE of CHANGE!