SOLUTION: The lengths of rectangles A and B are both four times as long as their widths. The lengths of rectangle A is three times the length of rectangle B. If the difference in the perimet

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Question 1024275: The lengths of rectangles A and B are both four times as long as their widths. The lengths of rectangle A is three times the length of rectangle B. If the difference in the perimeters is 16cm, find the dimensions of each rectangle.
Use simultaneous equations.
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Rectangle A
L+and+w
L=4w
2L%2B2w=perimA

Rectangle B
x+and+y
y=4x
2y%2B2x=perimB

system%28L=3y%2CperimA-perimB=16%29

system%28L=3y%2Cy=4x%2C2L%2B2w-%282y%2B2x%29=16%29
This seems to not be enough. Making the substitution for L and y, you would have one
equation but still two variables.