SOLUTION: Explain in words how to write an equation that is part one: parallel and then also part two: perpendicular to the equation y=2/3x-4 passing through the point (-2,-5). Write your

Algebra ->  Coordinate Systems and Linear Equations  -> Lessons -> SOLUTION: Explain in words how to write an equation that is part one: parallel and then also part two: perpendicular to the equation y=2/3x-4 passing through the point (-2,-5). Write your       Log On


   

Question 1013618: Explain in words how to write an equation that is part one: parallel and then also part two: perpendicular to the equation y=2/3x-4 passing through the point (-2,-5). Write your answer in standard form.
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Reference equation given, y=%282%2F3%29x-4. Slope is 2%2F3.
A line in the plane parallel also has slope 2%2F3; and a line in the plane perpendicular to the reference line has slope negative reciprocal, which is -3%2F2.

The parallel line through the given point (-2,-5) is y-%28-5%29=%282%2F3%29%28x-%28-2%29%29 which is written in point-slope form.

The perpendicular line through the given point is y-%28-5%29=%28-3%2F2%29%28x-%28-2%29%29, again being in point-slope form.

Starting those in point-slope form was easier than arranging for slope-intercept form. Use your algebra skill to put each of them into standard form.